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Grade upto college level Physical Chemistry

Using van der Waal’s equation, calculate the constant, ‘a’ when two moles of a gas confined in a four litre flask exerts a pressure of 11.0 atmospheres at a temperature of 300 K. The value of ‘b’ is 0.05 L mol-1.

Profile image of Amit Saxena
12 Years agoGrade upto college level
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1 Answer

Profile image of Navjyot Kalra
12 Years ago
van der waals equation for n moles of gas is
[P + n2a/V2] [V – nb] = nRT
Given V = 4 litre; P = 11.0 atm, T = 300 K;
b = 0.05 litre mol-1, n = 2 ;
thus, [11 + 22a/42] [4 – 2 *0.05] = 2 * 0.082 *300
a = 6.46 atm litre2 mol-2