Grade 12Physical Chemistry

Two substances A ( = 5 min) and B(= 15 min) are taken in such a way that initially [A] = 4[B]. The time after which both the concentrations will be equal is : (assume that reaction is first order

siddhu

7 Years agoGrade 12

1 Answer

Khimraj

7 Years ago

Initial conc of A = 4[B]

initial conc of B = [B]

conc of A after n1 half life = 4[B]/2ⁿ¹

conc of B after n2 half life = [B]/2ⁿ²

for conc of A = conc of B

4[B]/2ⁿ¹ = [B]/2ⁿ²

2^{(n1 – n2)} = 2²

n1 – n2 = 2 – (1)

also

t = n1*5 = n2*15

so n1 = 3*n2

so 3*n2 – n2 = 2

so n2 = 1

so time taken = 1*15 = 15 min

Hope it clears.....................

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Two substances A ( = 5 min) and B(= 15 min) are taken in such a way that initially [A] = 4[B]. The time after which both the concentrations will be equal is : (assume that reaction is first order

Two substances A ( = 5 min) and B(= 15 min) are taken in such a way that initially [A] = 4[B]. The time after which both the concentrations will be equal is : (assume that reaction is first order

siddhu

1 Answer

Khimraj

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