two particles A&B are in motion.if wavelength associated with particle A is 5*10(power=-8)m.calculate wavelength associated with particle B if its momentum is half of A....
rishang , 9 Years ago
Grade 11
1 Answers
Ashutosh Sharma
Last Activity: 9 Years ago
(mV)A=h/λ(A)---- (1) (mV)B=h/λ(B)------- (2) so from 1&2 (mV)B=12(mV)A therefore, hλB=h2λA=2×5×10−8m=10×10−8m=1000A∘
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