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Grade: 11
        
two particles A&B are in motion.if wavelength associated with particle A is 5*10(power=-8)m.calculate wavelength associated with particle B if its momentum is half of A....
4 years ago

Answers : (1)

Ashutosh Sharma
askIITians Faculty
181 Points
							(mV)A=h/λ(A)---- (1)
(mV)B=h/λ(B)------- (2)
so from 1&2 (mV)B=12(mV)A
therefore,
hλB=h2λA=2×5×10−8m=10×10−8m=1000A∘
4 years ago
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