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two particles A and B are in motion .If wavelength associated with the particle A is 5 *10^-8 m,calculate the wavelength associated with the paticle B if the momentum is half of a

gaurav , 8 Years ago
Grade 11
anser 1 Answers
Shivansh Saumya
E=hv
½.mv2= h.c/wavelength
v = (2hc/wavelength.m)1/2
v = ((2x6.626x10-34x3*108)/9.11x10-31x5 *10^-8)1/2
  = (8727991218441.273)½
  = 2954317.386 m/s
p of B = (me.v)/2
vb = v/2
 = 1477158.693 m/s
½.mv2= hc/wavelength
wavelength = 2hc/mv2
= 0.00005
 = 5*10-5 
Last Activity: 8 Years ago
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