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Grade: 11
        
two oxides oa a metal contain 72.4% and 70% of metal respectively? if formula of 2nd oxide isM2O3, find that of the first
2 years ago

Answers : (1)

Arun
24740 Points
							
Dear student
 
For Oxygen, we can calculate as w(%) = 100 -70 = 30
But Ar(O) = 16
Based on the law of proportion - [% / Ar], so according to it,
= 70/x : 30/16 = 2:3
= 70/x : 1.875 = 2:3, where x = 56 (Fe) 

So, if w(O) = 100 – 72.4 = 27.6 (%) 

=72.4/56 : 27.6/16 = 1.2928 : 1.725 = 1 : 1.334 = 3 : 4 
The answer should be - M3O4 (Fe3O4) 
 
 
Regards
Arun
2 years ago
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