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# Two nuetron and two protons from a helium nucles iduring fusion calculate released energy in the process

Eshan
3 years ago
Dear student,

Here the mass of neutrons and protons as well as a completely formed Helium nucleus must be given.

So the energy released would be equal to the mass difference of reactants and products multiplied by$\dpi{80} c^2$.

Hence energy released=$\dpi{80} (2m_p+2m_n-M_{He})c^2$
whereis the speed of light.