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Let A dissociates into two parts P and Q
So A -> P +Q
If c be the number of moles of A dissolved in 1L solution initially and a is the degree of dissociation then
Dissociation constant
K = (c2a2)/(c(1-a))
=>c = (K(1-a))/a2........(1)
Now if i be the vant hoff's factor of the solution of A . So effective molarity of the solution will be = ic. As the solution of A is isotonic with solution of B having molarity 10-3. We can say
ic= 10-3............(2)
Again i= 1+ a.........(3)
Given K = 10-5........(4)
Combining (1),(2),(3) and (4) we get
10-5×(1-a2)/a2 =10-3
=> 1/a2=101
So c = (K(1-a))/a2
c=10-5(1/a2-1/a)
=10-5(101-✓101)
=5.9×10-4
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