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Grade: 12
        

Two liquids containing non-volatile substance a(ionizable) and b(non-ionizable) respectively are isotonic. The molarity of solution containing b is 10-3 then what will be the molarity of solution containing a?

6 months ago

Answers : (1)

Arun
21013 Points
							

Let A dissociates into two parts P and Q

So A -> P +Q

If c be the number of moles of A dissolved in 1L solution initially and a is the degree of dissociation then

Dissociation constant 

K = (c2a2)/(c(1-a))

=>c = (K(1-a))/a2........(1)

Now if i be the vant hoff's factor of the solution of A . So  effective molarity of the solution will be = ic. As the solution of A is isotonic with solution of B having molarity 10-3. We can say 

ic= 10-3............(2)

 Again i= 1+ a.........(3)

Given K = 10-5........(4)

Combining (1),(2),(3) and (4) we get

10-5×(1-a2)/a2 =10-3

=> 1/a2=101

So  c = (K(1-a))/a2

c=10-5(1/a2-1/a)

=10-5(101-✓101)

=5.9×10-4

5 months ago
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