Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 12

Two liquids containing non-volatile substance a(ionizable) and b(non-ionizable) respectively are isotonic. The molarity of solution containing b is 10-3 then what will be the molarity of solution containing a?

one year ago

Answers : (1)

24497 Points

Let A dissociates into two parts P and Q

So A -> P +Q

If c be the number of moles of A dissolved in 1L solution initially and a is the degree of dissociation then

Dissociation constant 

K = (c2a2)/(c(1-a))

=>c = (K(1-a))/a2........(1)

Now if i be the vant hoff's factor of the solution of A . So  effective molarity of the solution will be = ic. As the solution of A is isotonic with solution of B having molarity 10-3. We can say 

ic= 10-3............(2)

 Again i= 1+ a.........(3)

Given K = 10-5........(4)

Combining (1),(2),(3) and (4) we get

10-5×(1-a2)/a2 =10-3

=> 1/a2=101

So  c = (K(1-a))/a2




one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details