Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Two liquids containing non-volatile substance a(ionizable) and b(non-ionizable) respectively are isotonic. The molarity of solution containing b is 10-3 then what will be the molarity of solution containing a?`
one year ago

Arun
24497 Points
```							Let A dissociates into two parts P and QSo A -> P +QIf c be the number of moles of A dissolved in 1L solution initially and a is the degree of dissociation thenDissociation constant K = (c2a2)/(c(1-a))=>c = (K(1-a))/a2........(1)Now if i be the vant hoff's factor of the solution of A . So  effective molarity of the solution will be = ic. As the solution of A is isotonic with solution of B having molarity 10-3. We can say ic= 10-3............(2) Again i= 1+ a.........(3)Given K = 10-5........(4)Combining (1),(2),(3) and (4) we get10-5×(1-a2)/a2 =10-3=> 1/a2=101So  c = (K(1-a))/a2c=10-5(1/a2-1/a)=10-5(101-✓101)=5.9×10-4
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions