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Two Faraday of electricityis passed through a solution of CuSO4. the mass of copper deposited at the cathode is (at. mass of cu =63.5 amu)

Vaddi Harshitha , 6 Years ago
Grade 12
anser 1 Answers
Mahima Kanawat

Last Activity: 6 Years ago

Dear student
No. Of Faraday = no. Of equivalents of Cu deposited
2 = wt of cu deposited /eq wt of cu
Wt of cu deposited = 63.5 g
WITH REGARDS 
MAHIMA 
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