Two closed vessel A and B of equal volume of 8.21L are connected by a narrow tube of negligible volume with open valve.The left hand side container is found to contain 3 mole CO2 and 2 mole He at 400 K.What is the partial pressure of He in vessel B at 500K
Vinay Pandey , 6 Years ago
Grade
1 Answers
Arun
Last Activity: 6 Years ago
P(CO2)=3*0.0821*400/8.21=12atm
P(He)=2*0.0821*400/8.21=8atm
Pressure at 55k
P1/T1=P2/T2
T1=400
T2=500
P1=8atm
8/400=p2/500
P2=4000/400=10atm.=the partial pressure of He in vessel B at 500 K
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