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Grade: 12th pass
        
total no. of voids in 0.5 mole of a compound forming hexagonal closed packed structure are
one year ago

Answers : (1)

Vignesh vijayakumar
29 Points
							0.5 mol contains  (6.022×10^23)/2 particles=3.011×10^23 particlesNo. Of octahedral voids=no. Of particles=3.011×10^23-------( 1)No. Of tetrahedral voids =2×no. Of particles=6.022×10^23 -----------(2)Hence Total voids = (1)+(2)=(3.011+6.022)×10^23=9.033×10^23
						
one year ago
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