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TOTAL NO OF VOID IN 0.5 MOLE OF COMPOUND FORMING HCP IS

avila varghese , 3 Years ago
Grade 12th pass
anser 1 Answers
Jayesh Vashishtha

Last Activity: 3 Years ago

Dear students,
Number of close-packed particles = 0.5×6.022×1023= 3.011×1023
Therefore, number of octahedral voids = 3.011×1023
And, number of tetrahedral voids = 2×3.011×1023= 6.022×1023
Therefore, total number of voids = 3.011×1023+ 6.022×1023= 9.033×1023


regards,
Team Askiitian’s

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