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Grade 11Physical Chemistry

The weight of silver carbonate that has to be strongly heated to get 4.64 g residue is

Profile image of Hrishikesh Mohan
9 Years agoGrade 11
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1 Answer

Profile image of Dayitva Goel
9 Years ago
The equation is 
Ag2CO3 ---} 2Ag + CO2 + O2
 
Molecular weight of Ag2CO3 = 276 g
Weight of 2Ag = 216 g
 
=} 216 g of Ag is given by heating 276g of Ag2CO3
=} 4.64 g of Ag is given by heating 276 × 4.46 / 216 = 5.698 g of Ag2CO3