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Grade 11Physical Chemistry

The wavelength of the radiation emitted when an electron falls from Bohr’s orbit 4 to 2 in hydrogen atom is

Profile image of adil
8 Years agoGrade 11
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1 Answer

Profile image of Kaustubh Mishra
8 Years ago
As we know the formula (Wavelength)^–1 = RZ^2 [(1/n1^2) – (1-n2^2)]Here, R = Rhydbergs Constant = 109677cm N1 =4 , N2=2. Z=1 (since it is hydrogen atom)By plugging these values in the formula we get Wavelength^-1 = 20564.43So wavelength = 0.0000486 cms OR 0.000000486 m OR 4.86 x10 ^-7 m