Grade 11Physical Chemistry
The volume of carbon dioxide gas evolved at STP by heating 7.3 gm of Mg(HCO3)2 will be?
1 Answer
ADARSH SINGH
on heating magnisium hydrogen carbonate,
following reaction takes place-
Mg(HCO3)2 = MgO + H2O + 2CO2
NOW , TOTAL MOLECULAR MASS OF Mg(HCO3)2 IS 146 AND THAT OF C02 IS 44.
THEREFORE, NO OF MOLES OF Mg(HCO3)2 PRESENT IN OUR REACTION= 7.3/146 = 0.05
THEREFORE BY UNITARY METHOD,
NO OF MOLES FORMED OF CO2 = 2 X 0.05 = 0.1 MOLE.
NOW, WE KNOW THAT IN STP, 1 MOLE OF ANY GAS HAS VOLUME 22.4L
THEREFORE VOLUME OF CO2 PRODUCED = 22.4 X 0.1 = 2.24 L
HOPE YOU GOT YOUR ANSWER .
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