badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 9

                        

The volume of a gas at STP is 1.12 x 10 -7 ml . Calculate the number of molecules present in the gas .

4 years ago

Answers : (4)

ARUNSOUMYA BASU
44 Points
							
At STP, a volume of 22400 mL is occupid by 6.023*1023 molecules of any gas.
So, 1.12 * 10-7mL is occupied by 6.023*1023 *1.12 * 10-7*22400-1 moleules or 3.0115 * 1012 molcules.
4 years ago
Vivek
13 Points
							At S.T.P 1mole=6.023×10^23 molecules which occupy a volume of 22400ml.Let the number of molecules present in 1.12×10^-7ml be `X`.So, 6.023×10^23 ×1.12*10^-7= X × 22400                            X=6.023×10^23 ×1.12*10^-7 ÷ 22400 Number of molecules (X)=3.01 ×10^12 molecules
						
2 years ago
Raghvendra kumar
11 Points
							
Here cc mean ml , so here at stp 22400 ml volume is occupied by 6.023 * 10²³ molecules
  1. To calculate no of molecules in 1.12*10¯7  volume of gas
  2. 1.12 * 10¯7​ * 6.023 * 10²³ divided by 22400
  3. No of molecumol is equal to 3.013* 10¹²
2 years ago
Rishi Sharma
askIITians Faculty
614 Points
							Dear Student,
Please find below the solution to your problem.

At S.T.P 1mole=6.023×10^23 molecules which occupy a volume of 22400ml.
Let the number of molecules present in 1.12×10^-7ml be `X`.
So, 6.023×10^23 ×1.12*10^-7= X × 22400
X=6.023×10^23 ×1.12*10^-7 ÷ 22400
Number of molecules (X)=3.01 ×10^12 molecules

Thanks and Regards
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details