Grade 9Physical Chemistry

The volume of a gas at STP is 1.12 x 10^-7ml . Calculate the number of molecules present in the gas .

Varun Gandhi

9 Years agoGrade 9

4 Answers

ARUNSOUMYA BASU

9 Years ago

At STP, a volume of 22400 mL is occupid by 6.023*10²³ molecules of any gas.

So, 1.12 * 10^-7mL is occupied by 6.023*10^{23 *}1.12 * 10^-7*22400^-1moleules or 3.0115 * 10¹² molcules.

Vivek

8 Years ago

At S.T.P 1mole=6.023×10^23 molecules which occupy a volume of 22400ml.Let the number of molecules present in 1.12×10^-7ml be `X`.So, 6.023×10^23 ×1.12*10^-7= X × 22400 X=6.023×10^23 ×1.12*10^-7 ÷ 22400 Number of molecules (X)=3.01 ×10^12 molecules

Raghvendra kumar

8 Years ago

Here cc mean ml , so here at stp 22400 ml volume is occupied by 6.023 * 10²³ molecules

To calculate no of molecules in 1.12*10¯⁷ volume of gas
1.12 * 10¯⁷ * 6.023 * 10²³ divided by 22400
No of molecumol is equal to 3.013* 10¹²

Rishi Sharma

6 Years ago

Dear Student,
Please find below the solution to your problem.

At S.T.P 1mole=6.023×10^23 molecules which occupy a volume of 22400ml.
Let the number of molecules present in 1.12×10^-7ml be `X`.
So, 6.023×10^23 ×1.12*10^-7= X × 22400
X=6.023×10^23 ×1.12*10^-7 ÷ 22400
Number of molecules (X)=3.01 ×10^12 molecules

Thanks and Regards