The vapour pressure of pure A is 10 and at same temperature when 1 g of B is dissolved in 20 g A, its vapour pressure is reduced to 9. The molecular weight of A is 200 amu then molecular weight of B is?
Mit patel
9 Years agoGrade 12
1 Answer
Vikas TU
9 Years ago
Us ethe Solutions and Colliative Properties chapter formulae that is:
Let PO = 10 ,Ps = 9 (P^o-P_s)/P_s = n_B/N_A (10-9)/9= □(□(1/M_B )) /□(20/200) Therefore, MB = 90amu.