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Grade 12Physical Chemistry

the vapour pressure of a solvent decreased by 10 mm Hg when a non -volatile solute was added to the solvent.The mole fraction of solute in solution is 0.2,what would be the mole fraction of solute if decrease in vapour pressure is 20mm of Hg.?

Profile image of Shriya Mehrotra
11 Years agoGrade 12
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4 Answers

Profile image of Naveen Kumar
11 Years ago
Dear student plz find the image attached here:
260-649_vp.png
Profile image of Tushar W
8 Years ago
P is vapour pressure of mixture.P° is vap pre. of pure solvent.Xis mole fraction of solute.Since ,Mole fraction of solute =0.2Therefore mole fraction of solvent =0.8.So, P-10=0.8()
Profile image of Khushboo
8 Years ago
P°-Ps=10 mmXsolute =0.2P°-Ps=20 mmXsolute =? From case 110/P°=0.2P°=50For case 2P°-Ps/P°=XsoluteXsolvent=20/50=2/5Xsolvent=1-2/5=3/5Hope it helps u!!!!
Profile image of ankit singh
5 Years ago
P is vapour pressure of mixture.P° is vap pre. of pure solvent.Xis mole fraction of solute.Since ,Mole fraction of solute =0.2Therefore mole fraction of solvent =0.8.So, P-10=0.8()
 
P°-Ps=10 mmXsolute =0.2P°-Ps=20 mmXsolute =? From case 110/P°=0.2P°=50For case 2P°-Ps/P°=XsoluteXsolvent=20/50=2/5Xsolvent=1-2/5=3/5Hope it helps u!!!!