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The vapour pressure of a dilute aqueous solution of glucose is 750 mm of mercury at 373 k. The mole fraction of solute is

Pushpendra taylor , 8 Years ago
Grade 12
anser 1 Answers
Indestructible Avinash
The answer to the question is 1/76=0.01315Proof: P°=760mm Ps=760mm mole fraction of solute = (P°-Ps)/P° (760-750)/760 = 0.01315
Last Activity: 8 Years ago
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