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Grade 12th passPhysical Chemistry

the vapor pressure of pure water at 25 °c is 23 torr.then the vapour pressure of 100g of water to which 100g of C6div2O6 has been added is

Profile image of Vishnu
8 Years agoGrade 12th pass
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1 Answer

Profile image of Parth Verma
8 Years ago
ans. 20.9 torr,
Explanation-
Apply the formula-
(P0 – Ps)/P0 = X, where P0 = vapour pressure of pure water, Ps = V.P. of solution, X = mole fraction of solute in solution.
Molar mass of glucose = 180 g, and molar mass of water = 18 g.
Now you have sufficient information to solve this problem.
Thanks.