Arun
Last Activity: 6 Years ago
Please find the answer to your question
Ptotal = pA + pB
Molecular weight of CH3OH = 12 + 3 + 16 + 1 = 32
Molecular weight of C2H5OH = 24 + 5 + 16 + 1 = 46
According to Raoult’s law
Ptotal = p1 + p2
Where Ptotal = Total vapour pressure of the solution
P1 = Partial vapour pressure of one component
P2 = Partial vapour pressure of other componenet
Again, p1 = Vapour pressure (po1) * mole fraction
Similarly, p2 = Vapour pressure (po2) * mole fraction
Mole fraction of CH3OH = 12/32 /(12/32+48/46) = 0.264
Mole fraction of ethanol = 48/46 /(48/46+12/32) = 0.735
NOTE THIS STEP : Thus now let us first calculate the partial vapour pressures, i.e., p1 and p2 of the two component.
Partial vapour pressure of CH3OH(p1)
= 90 * 0.264 = 23.76 mm
∴ Total vapour pressure of the solution
= 29.4 + 23.76 mm = 53.16 mm
Mole fraction of CH3OH in vapour = 23.76/53.16 = 0.44