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\tthe uncertainity in momentum of an electron is 1×10-5kg.m/s. the uncertainity in its position will be[h=6.62×10-34kg.m/s

lokesh , 10 Years ago
Grade 11
anser 1 Answers
Aarti Gupta

Last Activity: 10 Years ago

Given - Uncertainity in momentum , delta p = 1*10-5 kgm/s
Planck’s constant h = 6.62 * 10-34 kgm/s
Uncertainity in position,delta x = ?
Sol.-
According to Heisenberg uncertainity principle,
deltax * deltap = h/4pi
deltax = h/4pi * deltap
= 6.62 * 10-34/4*3.14*1*10-5
deltax = 5.27 * 10-30 m
Thus uncertainity in position = 5.27 * 10-30 m

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