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The temperature of a gas present in a closed vessel is increased by 5°C so that it`s pressure is increased by 1%.find out initial temperature of gas
As vessel is closed , so volume of the container is constant.P proportional to Twhere P = pressure and T= temperatureso,P1/P2 = T1/T2now pressure in increased by 1%HenceP2 = P1 + P1*1/100 = 1.01 P1T2 = T1+5so,P1/1.01P1 = T1/T1+5T1+ 5 = 1.01 T10.01 T1 = 5T1 = 500 KT1 = 227°C
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