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The specific conductance of a 0.01 M solution of kcl is 0.0014 ohm inverse CM inverse at 25 degree Celsius. It`s equivalent conductance is?
Specific conductance (k)=0.0014 ohm^-1 cm^-1Molarity of kcl = 0.01MNow...we know thatEquivalent conductance= k×1000/normalityNormality of 0.01 M kcl is 0.01N.........bcz n=1.........for kclHence,. Equivalent conductance = 0.0014×1000/0.001= 140 cm^2ohm^-1eq^-1
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