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The specific conductance of a 0.01 M solution of kcl is 0.0014 ohm inverse CM inverse at 25 degree Celsius. It`s equivalent conductance is?

Subhash , 8 Years ago
Grade 12
anser 1 Answers
Tanaya Ronghe

Last Activity: 7 Years ago

Specific conductance (k)=0.0014 ohm^-1 cm^-1
Molarity of kcl = 0.01M
Now...we know that
Equivalent conductance= k×1000/normality
Normality of 0.01 M kcl is 0.01N.........bcz n=1.........for kcl
Hence,. Equivalent conductance = 0.0014×1000/0.001
= 140 cm^2ohm^-1eq^-1
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