Tanaya Ronghe
Last Activity: 7 Years ago
Specific conductance (k)=0.0014 ohm^-1 cm^-1
Molarity of kcl = 0.01M
Now...we know that
Equivalent conductance= k×1000/normality
Normality of 0.01 M kcl is 0.01N.........bcz n=1.........for kcl
Hence,. Equivalent conductance = 0.0014×1000/0.001
= 140 cm^2ohm^-1eq^-1