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The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 ?. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1.?

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 ?. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1.?

Grade:8

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
6 years ago
As The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500
conductivity=cell constant/resistance
Thus cell constant=conductivity*resistance
here conductivity=.146*10^-3Scm^-1
resistance=1500 ohm
cell constant=1500*.146*10^-3
=.219 cm^-1

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