The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 ?. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1.?
prasanjeet kumar
12 Years agoGrade 8
1 Answer
Sunil Kumar FP
11 Years ago
As The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 conductivity=cell constant/resistance Thus cell constant=conductivity*resistance here conductivity=.146*10^-3Scm^-1 resistance=1500 ohm cell constant=1500*.146*10^-3 =.219 cm^-1