The relative decrease in vapour pressure of an aqueous solution containing 2 mole NaCl in 3 mole H2O is 0.40 . on reaction with agno3 this solution will form
Geetha
8 Years agoGrade 12
2 Answers
sid dwivedi
6 Years ago
From RLVP , we get
.4 = i(1)/ i(1) + 3
So i = 2
Dissociation of Nacl
Na^+ + cl^-
i = 1 + alpha
Then 1+ alpha = 2 so alpha = 1
Means 100% ionization
Means 100% ionization
Vikas TU
6 Years ago
Dear student Relative lowering in vapour pressure del p / p^0 = inb /(inb +na +...) del p = p^0 -p For Agcl = 3mol - 2mol = 1mole gcl Hope this helps Good Luck