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The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K. Calculate Ea?

The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K. Calculate Ea?

Grade:8

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
7 years ago
The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K
log(k2/k1)=Ea/2.303 R(1/T1-1/T2)
it inpleis from the above value that
log2=Ea/2.303*8.314(1/298-1/308)
Ea=53KJ
The energy of activation is the minimum energy for a reaction to have in order to proceed in a given direction

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