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Grade 8Physical Chemistry

The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K. Calculate Ea?

Profile image of prasanjeet kumar
12 Years agoGrade 8
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1 Answer

Profile image of Sunil Kumar FP
11 Years ago
The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K
log(k2/k1)=Ea/2.303 R(1/T1-1/T2)
it inpleis from the above value that
log2=Ea/2.303*8.314(1/298-1/308)
Ea=53KJ
The energy of activation is the minimum energy for a reaction to have in order to proceed in a given direction