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        the rate of reaction triples when temperature changes from 20celcious to 50celcious. Energy of activation for the reaction is
2 years ago

Arun
22972 Points
							The Arrhenius equation is log10k2k1=Ea(R×2.303)[(T2–T1)(T1T2)]Given:  k2k1 = 3; R=8.314 JK-1 mol–1; T1 = 20 + 273 = 293 Kand   T2 = 50 + 273 = 323 KSubtracting the given values in the Arrhenius equation,log10 3 = Ea(8.314×2.303)[(323 − 293)(323 × 293)]Ea = (2.303 × 8.314×323 × 293×0.477)/30= 28811.8 J mol-1= 28.8118 kJ mol.-1

2 years ago
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