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The rate of diffusion of 2 gases A and B are in the ration 16:3 If the ration of their masses present in the misture is 2:3 Then a,. Then ratio o their molar masses is 16:1 b.. The ratio of thier molar masses is 1:4 c the ratio of their moles present inside the container is 1:24 d the ratio of their moles present inside the container is 8:3
The rate of diffusion of 2 gases A and B are in the ration 16:3 If the ration of their masses present in the misture is 2:3 Then a,. Then ratio o their molar masses is 16:1b.. The ratio of thier molar masses is 1:4 c the ratio of their moles present inside the container is 1:24d the ratio of their moles present inside the container is 8:3

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4 years ago

```							We know the rate of diffusion formulae:Therefore,R1/R2 => 16/3 = (2x/M1)A/M1root(M1T)     *  M2root(M2T)/3xwe get M2/M1 = 64^(1/3) = 4/1and hence,M1/M2 = 1:4 is the answer.where 2x/M1 = moles for A gas and3x/M2 = moles for B gas respectively.And we have placed them for pressure as from ideal gas eqn. Pressure is proprotional to the moles of the gases keeping the temperature constant.Henceoption b.
```
4 years ago
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