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Grade 11Physical Chemistry

The rate of diffusion of 2 gases A and B are in the ration 16:3 If the ration of their masses present in the misture is 2:3 Then

a,. Then ratio o their molar masses is 16:1
b.. The ratio of thier molar masses is 1:4
c the ratio of their moles present inside the container is 1:24
d the ratio of their moles present inside the container is 8:3

Gaurang Kotasthane

9 Years agoGrade 11

1 Answer

Vikas TU

9 Years ago

We know the rate of diffusion formulae:

Therefore,

R1/R2 => 16/3 = (2x/M1)A/M1root(M1T) * M2root(M2T)/3x

we get M2/M1 = 64^(1/3) = 4/1

and hence,

M1/M2 = 1:4 is the answer.

where 2x/M1 = moles for A gas

and

3x/M2 = moles for B gas respectively.

And we have placed them for pressure as from ideal gas eqn. Pressure is proprotional to the moles of the gases keeping the temperature constant.

Hence

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