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Grade: 11
        The rate of a first-order reaction is 0.04 mol l^-1 s^-1 at 10 seconds and 0.03 mol l^-1 s^-1 at 20 seconds after initiation of the reaction The half life period of the reaction is
one year ago

Answers : (1)

Vikas TU
6887 Points
							
 U have to just put the values into the formulae for the first order eqn. that is:
K = (2.303/t2 –  t1)log(Q1/Q2)
   =(2.303/(10)llog(0.04/0.03)
After solving,
K = 0.02876 /min
thalf = 0.693/k = > 24 min approx.
one year ago
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