Grade 12Physical ChemistryThe rate constant of a certain reaction is given by logk=5.4-212÷T calculate activation energy at 127 Celsius Rituraj 9 Years agoGrade 12
Vikas TU9 Years agoFrom the formulae:k = Ae^(-Ea/RT)logk = logA – 2.303Ea/RT...........(1)Given eqn. is:logk = 5.4 - 212/T …..................(2)Compariing both the eqns. we get,2.303Ea/R = 212Ea = > 212*25/(3*2.303) => 767.11 J