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Grade 12Physical Chemistry

The rate constant of a certain reaction is given by logk=5.4-212÷T calculate activation energy at 127 Celsius

Profile image of Rituraj
9 Years agoGrade 12
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1 Answer

Profile image of Vikas TU
9 Years ago
From the formulae:
k = Ae^(-Ea/RT)
logk = logA – 2.303Ea/RT...........(1)
Given eqn. is:
logk = 5.4 - 212/T …..................(2)
Compariing both the eqns. we get,
2.303Ea/R = 212
Ea = > 212*25/(3*2.303) =>  767.11 J