Sahani Kumar
Last Activity: 6 Years ago
Concentration of HCl= (0.1*40)/1000= 0.004 mol/L
Concentration of NaOH= (0.45*10)/1000 = 0.0045 mol/L
0.004 mol/L of HCl will produce 0.004 mol/L H+ ions.
0.0045 mol/L of NaoH will produce 0.0045 mol/L
OH- ions.
But 0.004 H+ ion will netralise0.004 OH-ion.
Thus only 0.0005 mol/L OH- ion will be left free
after neutralisation and only these only will
contribute to pH of the solution.
Now, -pOH=log[OH-] -pOH=log[5 * 10^-4]
-pOH=log5+ log(10^-4)
-pOH=0.699 – 4. pOH=4 – 0.699
pOH=3.301
pH=pKw – pOH. pH=14 – 3.301
pH=10.699
