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The pH of solution formed by mixing 40 ml of 0.1M HCl with 10 ml 0.45 M of NaOH is ? Please answer quickly
Concentration of HCl= (0.1*40)/1000= 0.004 mol/LConcentration of NaOH= (0.45*10)/1000 = 0.0045 mol/L0.004 mol/L of HCl will produce 0.004 mol/L H+ ions. 0.0045 mol/L of NaoH will produce 0.0045 mol/LOH- ions.But 0.004 H+ ion will netralise0.004 OH-ion.Thus only 0.0005 mol/L OH- ion will be left freeafter neutralisation and only these only willcontribute to pH of the solution. Now, -pOH=log[OH-] -pOH=log[5 * 10^-4] -pOH=log5+ log(10^-4) -pOH=0.699 – 4. pOH=4 – 0.699 pOH=3.301 pH=pKw – pOH. pH=14 – 3.301 pH=10.699
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