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Grade 12Physical Chemistry

The pH of 0.02M NH4Cl (p^kb=4.73) is equal to ?

Profile image of lokesh palingi
12 Years agoGrade 12
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1 Answer

Profile image of Sunil Kumar FP
12 Years ago
pkw=14
pkb=4.73
logc=log(.02)=-1.69
ph=1/2pkw-1/2logc-1/2pkb
=1/2×14 -1/2×(-1.69) -1/2(4.73)
=5.48

thanks and regards
sunil kr
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