Grade 11Physical Chemistry
The Percentage of nitrogen in urea is about?A) 46. B)85C)18. D)28
2 Answers
sankalp
46%
urea=> NH2-CO-NH2
total mass=60
mass of nitrogen = 14, 2 molecules hence m=28
N%= mass of nitrogen X 100
mass of urea
= 28 X 100
60
N%= 46.6%
Kushagra Madhukar
Dear student,
Please find the attached solution to your problem.
Molecular formula of urea is NH2-CO-NH2
Hence, Molar mass = 60g
mass of nitrogen in 1 mole of Urea = 14*2 = 28g
Hence, percentage of Nitrogen = mass of nitrogen/mass of urea X 100
= 28/60 x 100
= 46.6%
Hope it helps
Thanks and regards,
Kushagra
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