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The Percentage of nitrogen in urea is about?A) 46.B)85C)18.D)28

Kashish , 7 Years ago
Grade 11
anser 2 Answers
sankalp

Last Activity: 7 Years ago

46%
 
urea=> NH2-CO-NH
total mass=60
mass of nitrogen = 14, 2 molecules hence m=28
N%= mass of nitrogen X 100
         mass of urea
  = 28  X 100
     60
  N%= 46.6%

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the attached solution to your problem. 
Molecular formula of urea is NH2-CO-NH
Hence, Molar mass = 60g
mass of nitrogen in 1 mole of Urea = 14*2 = 28g
Hence, percentage of Nitrogen = mass of nitrogen/mass of urea X 100
= 28/60 x 100
 = 46.6%
 
Hope it helps
Thanks and regards,
Kushagra

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