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The oxidation number of C in C H 2 ​ O is : A − 2 B + 2 C 0 D + 4

The oxidation number of C in CH2​O is :

A

−2

B

+2

C

0

D

+4

 

Grade:11

1 Answers

aman p
31 Points
3 years ago
dear student  
Let x be the oxidation state of C in CH 
2
​
 O.
Since, the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0.
Therefore,
x+2−2=0
or, x=0.
Hence, the oxidation state of C in CH 
2
​
 O is 0.

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