Grade 12th passPhysical Chemistry
The number of moles of k2Cr2O7 reduced by one mole of Sn2+ ions is _____?
The number of moles of k2Cr2O7 reduced by one mole of Sn2+ ions is _____?
1 Answer
Arun
Approved Tutor Answer7 Years agoK2Cr2O7 ---------> 2K+ + CrO72-
Cr2O72−(aq) + 14H+ + 6e− → 2Cr3+(aq) + 7H2O (source wiki)
Sn2+ ------------> Sn4+ +2e-
You can see each Cr2O72- ion gains 6 electrons and Sn+2 loses two electrons each to form Sn4+
therefore you need 3 moles of Sn+2 to reduce 1 mole of K2Cr2O7
( so your answer is a 1/3 mole of K2Cr2O7)
full equation looks like this
Cr2O72- + 3Sn2+ +14H+ -------------------> 3Sn4+ + 2Cr3+ + 7H2O
Cr2O72−(aq) + 14H+ + 6e− → 2Cr3+(aq) + 7H2O (source wiki)
Sn2+ ------------> Sn4+ +2e-
You can see each Cr2O72- ion gains 6 electrons and Sn+2 loses two electrons each to form Sn4+
therefore you need 3 moles of Sn+2 to reduce 1 mole of K2Cr2O7
( so your answer is a 1/3 mole of K2Cr2O7)
full equation looks like this
Cr2O72- + 3Sn2+ +14H+ -------------------> 3Sn4+ + 2Cr3+ + 7H2O
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