the number of atoms present in unit cell of diamond
akash takalkar
9 Years agoGrade 12
1 Answer
Khimraj
9 Years ago
(1/8* 8){8 present of corner} +(1/2 * 6){6 present on face centre} + 4(tetrahedrally bonded atoms in the unit cell) = 8. Hope it clears. If u have doubts then please clearify. And if u like my answer then please approve answer