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The number of atoms present in 4.25 grams of NH3 is approximately

The number of atoms present in 4.25 grams of NH3 is approximately

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Grade:12

4 Answers

Arun
25750 Points
6 years ago

Molar mass NH3 = 14+3 = 17g/mol
given mass = 4.25g

no of moles = 4.25/17 = 0.25 mol of NH3

1 mol of NH3 contains  6.022*10^23  molecules
0.25 mol NH3 contains  0.25*6.022*10^23  = 1.5055*10^23 molecules

1 molecule of NH3 contains 4 atoms
Number of atoms in 1.5055*10^23 molecules = 4*1.5055*10^23 atoms.

The correct answer is = 6.022*10^23 atoms

Chhavi Jain
92 Points
6 years ago
Dear student , 
 
 the molar mass of NH3  = 14 + 3*1 =17
now, we will first calculate the no. of moles of NH3 :
no. of moles = given mass / molar mass
                     = 4.25 / 17 =0.25 moles of NH3
 
as , in 1 mole of NH3,  no. of molecules of NH3 = 6.022 * 1023  ( Avogadro’s number )
therefore, in 0.25 moles of NH3 ,  no. of molecules of NH3 = 0.25 * 6.022 * 1023  = 1.5055 * 1023
 
as we know, in 1 molecule of NH3 , no. of atoms = 4 ( 1 atom of nitrogen and 3 atoms of hydrogen )
 
so, in 1.5055 *1023  molucules of NH3 ,  total no. of atoms = 4 * 1.5055 * 1023 =  6.022 * 1023  atoms 
 
Chemistry Consultant
askiitians
 
 
 
 
Anjali kumari
104 Points
5 years ago
As mole=given mass/molecular mass.So mole of NH3 =4.25/20=425/2000. = 0.25 mole So number of atoms=0.25×6.022×10^23 atoms.
Anjali kumari
104 Points
5 years ago
As molecular mass of NH3 is 14+3=17g.And as moke= given mass /molecular mass=4.25/17= 0.25mole Now number of atims=0,.25×6.022×10^23 atoms.

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