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`        The number of atoms present in 4.25 grams of NH3 is approximately`
2 years ago

```							Molar mass NH3 = 14+3 = 17g/molgiven mass = 4.25gno of moles = 4.25/17 = 0.25 mol of NH31 mol of NH3 contains  6.022*10^23  molecules0.25 mol NH3 contains  0.25*6.022*10^23  = 1.5055*10^23 molecules1 molecule of NH3 contains 4 atomsNumber of atoms in 1.5055*10^23 molecules = 4*1.5055*10^23 atoms.The correct answer is = 6.022*10^23 atoms
```
2 years ago
```							Dear student ,   the molar mass of NH3  = 14 + 3*1 =17now, we will first calculate the no. of moles of NH3 :no. of moles = given mass / molar mass                     = 4.25 / 17 =0.25 moles of NH3 as , in 1 mole of NH3,  no. of molecules of NH3 = 6.022 * 1023  ( Avogadro’s number )therefore, in 0.25 moles of NH3 ,  no. of molecules of NH3 = 0.25 * 6.022 * 1023  = 1.5055 * 1023 as we know, in 1 molecule of NH3 , no. of atoms = 4 ( 1 atom of nitrogen and 3 atoms of hydrogen ) so, in 1.5055 *1023  molucules of NH3 ,  total no. of atoms = 4 * 1.5055 * 1023 =  6.022 * 1023  atoms  Chemistry Consultantaskiitians
```
2 years ago
```							As mole=given mass/molecular mass.So mole of NH3 =4.25/20=425/2000. = 0.25 mole So number of atoms=0.25×6.022×10^23 atoms.
```
2 years ago
```							As molecular mass of NH3 is 14+3=17g.And as moke= given mass /molecular mass=4.25/17= 0.25mole Now number of atims=0,.25×6.022×10^23 atoms.
```
2 years ago
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