the no. of mole kmo4 that will need to react completely with one mole ferrous oxalate in acidic solution is:

KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2KMnO4 = 5 electronsferrous oxalate in acidic solution = 3 electronswhile reaction exchange of electrons takes place..........so3 moles of KMnO4 = 5 moles of FeC2O45 moles of FeC2O4 = 3 moles of KMnO4so 1 mole of FeC2O4 = 3/5 moles of KMnO4hence 3/5 moles of KMnO4 of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....