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The molar volumes of ice and water are 0.0196 and 0.0180 litres per mole at 273K. If ΔH for the transition of ice to water is 1440 calories per mole at 1 atm pressure, find ΔU.

The molar volumes of ice and water are 0.0196 and 0.0180 litres per mole at 273K. If ΔH for the transition of ice to water is 1440 calories per mole at 1 atm pressure, find ΔU.

Grade:11

1 Answers

Vikas TU
14149 Points
4 years ago
From eqn.
ΔU   +  Δ(PV)ΔH = 
        = ΔU   +  ΔPV + PΔV
      Given,
1440 = ΔU  + 0.0196*273 + 0.0180*273
ΔU = 1440  – 10.2648
      =  1429.73 calories.
 

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