Grade 11Physical ChemistryThe molar volumes of ice and water are 0.0196 and 0.0180 litres per mole at 273K. If ΔH for the transition of ice to water is 1440 calories per mole at 1 atm pressure, find ΔU. Rohit Kundu 9 Years agoGrade 11
Vikas TU9 Years agoFrom eqn.ΔU + Δ(PV)ΔH = = ΔU + ΔPV + PΔV Given,1440 = ΔU + 0.0196*273 + 0.0180*273ΔU = 1440 – 10.2648 = 1429.73 calories.