Grade 12Physical ChemistryThe molar volume of kal and nacl are 37.46 ml & 27.94 ml respectively. The ratio of the unit cube edges of the crystals is? bhumika gupta 9 Years agoGrade 12
Vikas TU9 Years agoFrom,Vm = 4*pi*r1^3*Na/3we get,r1 = (3Vm/(4*pi*Na))^(1/3) = (3*37.46/4pi*Na)^(1/3)and similarly for Nacl we get,r2 = (3*27.94/4pi*Na)(1/3)dividing both we get the ratio as:r1/r2 = 1.105/1 or => 11:10