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Grade: 12
        The molar volume of kal and nacl are 37.46 ml & 27.94 ml respectively. The ratio of the unit cube edges of the crystals is?
2 years ago

Answers : (1)

Vikas TU
9499 Points
							
From,
Vm = 4*pi*r1^3*Na/3
we get,
r1 = (3Vm/(4*pi*Na))^(1/3)
   = (3*37.46/4pi*Na)^(1/3)
and similarly for Nacl we get,
r2 = (3*27.94/4pi*Na)(1/3)
dividing both we get the ratio as:
r1/r2 = 1.105/1 or => 11:10
2 years ago
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