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The molar enthalpy of vaporization of benzene at it's boiling point (353K) is 30.84Kj/mol. What is the molar internal energy change? For how long would ba 12V source need to supply a 0.5 A current in order to vaporise 7.8 g of yth sample at its boiling point. Plz explain method Thanks by Shailwi

The molar enthalpy of vaporization of benzene at it's boiling point (353K) is 30.84Kj/mol. What is the molar internal energy change? For how long would ba 12V source need to supply a 0.5 A current in order to vaporise 7.8 g of yth sample at its boiling point.
Plz explain method
Thanks by Shailwi

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1 Answers

Avni Chauhan
askIITians Faculty 247 Points
5 years ago
\Delta H = \Delta E + \Delta nRT

benzene liquid is being converted to vapours, hence\Delta n = 1

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