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Grade 11Physical Chemistry

The line at 434 nm in the balmer series of the hydrogen spectrum corresponds to transition from the nth orbit to second Bohr orbit. What is the value of n? Ans: n=5

Profile image of Abhinav Acharya
12 Years agoGrade 11
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1 Answer

Profile image of siddharth gupta
ApprovedApproved Tutor Answer12 Years ago
RZ2(1/(n1)2-(1/(n2)2)=1/lambda
put R=1.09678 x 107 m-1 ,Z=1 ,n1=2 and lambda=434 X 10-9 m
solve the equation so formed and you will get only an aprroximate answer nearly equal to 5.
WITH REGARDS
SIDDHARTH GUPTA.