Grade 11Physical ChemistryThe kinetic energy of an electron in H like atom is 6.04eV. The area of the third Bohr orbit to which this electron belong is1. 1.78×10^-16 cm^22. 17.80×10^-16 cm^23. 35.6×10^-16 cm^24. 3.56×10^-16 cm^2 Asmita Pandey 8 Years agoGrade 11
Arun8 Years agoDear Student K.E. = 6.04 ev = 9.7 * 10^-19 JK.E. of electron = Kze²/2rK = constant = 9* 10^9 Nm²/C²z = 1( for hydrogen like atom)e = 1.6 * 10^-19 CHence put all this in the above formulaYou will getr = 1.19 * 10^-10 metresHence area A = (3.14159) * r²A= 17.8 * 10^-20 m²Or A = 17.8 * 10^-16 cm² Hence option 2 is correct. RegardsArun (AskIITians Forum Expert)