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the kinetic energy of an electron in H like atom is 6.04 eV. the area of the third bohr orbit to which this electron belong is; the kinetic energy of an electron in H like atom is 6.04 eV. the area of the third bohr orbit to which this electron belong is;
K.E. = 6.04 ev = 9.7 * 10^-19 JK.E. of electron = Kze²/2rK = constant = 9* 10^9 Nm²/C²z = 1( for hydrogen like atom)e = 1.6 * 10^-19 CHence put all this in the above formulaYou will getr = 1.19 * 10^-10 metresHence area A = (3.14159) * r²A= 17.8 * 10^-20 m²
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