The henry law constant for the solubility of N2 gas in water at 298k is 1×10^5atm.the mole fraction of N2 in air is 0.8.thw no. Of moles of N2 from air dissolved in 10 moles of water at 298k and 5 atm pressure is

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Arun · Answer

PN2 = KH x mole- fraction (N2) mole-fraction (H2) 1/105 x 0.8 x 5 = 4 x 10-5 mol-1 In 10 mole solubility is 4 x 10-4.

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The henry law constant for the solubility of N2 gas in water at 298k is 1×10^5atm.the mole fraction of N2 in air is 0.8.thw no. Of moles of N2 from air dissolved in 10 moles of water at 298k and 5 atm pressure is

The henry law constant for the solubility of N2 gas in water at 298k is 1×10^5atm.the mole fraction of N2 in air is 0.8.thw no. Of moles of N2 from air dissolved in 10 moles of water at 298k and 5 atm pressure is

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The henry law constant for the solubility of N2 gas in water at 298k is 1×10^5atm.the mole fraction of N2 in air is 0.8.thw no. Of moles of N2 from air dissolved in 10 moles of water at 298k and 5 atm pressure is

The henry law constant for the solubility of N2 gas in water at 298k is 1×10^5atm.the mole fraction of N2 in air is 0.8.thw no. Of moles of N2 from air dissolved in 10 moles of water at 298k and 5 atm pressure is

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