The heat of neutralization of LiOH and H₂SO₄ at 25⁰C is 69.6 KJ/mol. Calculate the heat of ionization of LiOH-

a.90KJ/mol b.22.5KJ/mol

Dear Student,
For the complete neuralization of a strong acid with a strong base the enthalpy change is -56 kJ/mol.
Here, Two moles of LiOH would react with one mole of the H2SO4.
If LiOH was completely dissociated the energy liberated would have been -112 kJ/mol.
So the energy or enthalpy used for the ionization is -112+69.6
= 42.4 KJ
For 1 mole of LiOH it would be 21.2 KJ