Piyush Kumar Behera
Last Activity: 8 Years ago
C6H6 + 15/2 O------> 6 CO2 + 3H2O
Heat liberated on complete combustion of 7.8 g or benzene = 327 kJ
∴Heat liberated on complete combustion of 78 g (1mol) of benzene = 327 kJ
Δn = 6-7 ½ = -1.5
R = 8.3 × 10 kJ mole K
T = 300 K
ΔH = ΔE + ΔngRT;
= -327kJ + (-1.5) (8.314 × 10 ) (300) kJ mole-1
-327 -3.7413 = 330.7413 KJ
So the answer is 330.7413