Grade 12th passPhysical Chemistrythe flux of the E=3i+24j+6k through a portion of 5m^2 of the plane the normal to which is 2i+4j+6k Anshu patel 6 Years agoGrade 12th pass
Vikas TU6 Years agoDear student E = 3i + 24j + 6k So, area vector magnitude = 5 and it is normal to 2i+ 4j +6karea vector = 5k Flux = E.dA Flux = (3i+24j+6k ). 5k => 30k