Question icon
Grade 12th passPhysical Chemistry

the flux of the E=3i+24j+6k through a portion of 5m^2 of the plane the normal to which is 2i+4j+6k

Profile image of Anshu patel
6 Years agoGrade 12th pass
Answers icon

1 Answer

Profile image of Vikas TU
6 Years ago
Dear student 
E = 3i + 24j + 6k 
So, area vector magnitude = 5 
and it is normal to 2i+ 4j +6k
area vector = 5k 
Flux = E.dA 
Flux = (3i+24j+6k ). 5k 
=> 30k