Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the attached answer to the problem
The degree of dissociation is related to equivalent conductance and equivalent conductance at infinite dilution :
The degree of dissociation α = Λ(equivalent conductance at given dilution)/Λ∞(equivalent conductance at given dilution)
= 8 mho cm2/400 mho cm2
Dissociation constant of an acid Ka = C α2
= 1/32 M x (8 mho cm2/400 mho cm2)2
= 1.25 x 10-5
Hope it helps.
Thanks and regards,
Kushagra