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the equilibrium constant kp for the following reaction at 191 degree celcius is 1.24. what is kc ? b(s) + 3/2f 2(g) = BF 3

the equilibrium constant kp for the following  reaction at 191 degree celcius is 1.24. what is kc ? 
               b(s) + 3/2f2(g) = BF3

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear Rahul
 
Use formula
 
Kp = Kc * (RT)^(delta n)
 
Now I hope you can do it. 
 
In case of any difficulty, Please feel free to ask.

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